# the summer of 20X2, the joint costs of processing the tomatoes were \$420,000. There was no beginning or ending inventories for the summer. Production and sales value information for the summer is as follows:ProductCasesSales Value at Splitoff PointSeparable CostsSelling PriceCatsup100,000\$6 per case\$3.00 per case\$28 per caseJuice150,0008 per case5.00 per case25 per caseCanned200,0005 per case2.50 per case10 per caseQuestion: Determine the amount allocated to each product if the estimated net realizable value method is used, and compute the cost per case for each product. (10 points) Problem 2 - Zenon Chemical, Inc. processes pine rosin into three products: turpentine, paint thinner, and spot remover. During May, the joint costs of processing were \$240,000. Production and sales value information for the month is as follows:ProductUnits ProducedSales Value at Splitoff PointTurpentine6,000 liters\$60,000Paint thinner6,000 liters50,000Spot remover3,000 liters25,000Question: Determine the amount of joint cost allocated to each product if the physical-measure method is used. (10 points)Problem 3 - Oregon Lumber processes timber into four products. During January, the joint costs of processing were \$280,000. There was no inventory at the beginning of the month. Production and sales value information for the month is as follows: Sales Value atProductBoard feetSplitoff PointEnding Inventory2 x 4's6,000,000\$0.30 per board foot500,000 bdft.2 x 6's3,000,0000.40 per board foot250,000 bdft.4 x 4's2,000,0000.45 per board foot100,000 bdft.Slabs1,000,0000.10 per board foot50,000 bdft.Question: Determine the value of ending inventory if the sales value at splitoff method is used for product costing. Round to three decimal places when necessary. (10 points)Solution details:STATUS Answered QUALITY Approved ANSWER RATING This question was answered on: Apr 19, 2020 PRICE: \$15 Solution~000.zip (25.37 KB) Buy this answer for only: \$15 This attachment is locked × Please Enter The Email Where You Want To Receive Solution. Get this solution for only: \$

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